Building Browsergames - Latest Comments in Building Browsergames: Implementing a flexible stats system (PHP)

Re: Building Browsergames: Implementing a flexible stats system (PHP)

Rado — Sun, 24 Nov 2013 12:20:35 -0000

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '<foo> OR short_name = <foo>) AND user_id = <bar> LIMIT 0, 30' at line 1

Re: Building Browsergames: Implementing a flexible stats system (PHP)

Sun — Wed, 15 May 2013 14:31:44 -0000

Le code SELECT value FROM user_stats WHERE stat_id = <foo> AND user_id = <bar>

Ne marche plus Il me mette

Error

There seems to be an error in your SQL query. The MySQL server error
output below, if there is any, may also help you in diagnosing the
problem

ERROR: Unknown Punctuation String @ 189
STR: AND stats.short_name = <foobar> AND user_stats.user_id = <bar> </bar></foobar></foo>

SQL query:

SELECT user_stats.value FROM user_stats INNER JOIN stats ON
(user_stats.stat_id = stats.id) WHERE stats.display_name = <foo>
AND stats.short_name = <foobar> AND user_stats.user_id =
<bar> </bar></foobar></foo>

MySQL said:

#1064 - You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near '<foo> AND stats.short_name = <foobar> AND
user_stats.user_id = <bar> </bar></foo'>

Re: Building Browsergames: Implementing a flexible stats system (PHP)

disqus_Xx2ZV5yudQ — Sat, 12 Feb 2011 18:10:31 -0000

In what file does this code actually go? Thanks!

Re: Building Browsergames: Implementing a flexible stats system (PHP)

Luke — Thu, 26 Nov 2009 10:15:02 -0000

Thanks for the tip, Name!

Re: Building Browsergames: Implementing a flexible stats system (PHP)

Name — Thu, 26 Nov 2009 06:11:15 -0000

Don't use subqueries, where an inner join is more likely (and probably faster).

Change this:

SELECT value FROM user_stats WHERE stat_id = ( SELECT id FROM stats WHERE display_name = <foo> OR short_name = <foo>) AND user_id = <bar>

to this:

SELECT user_stats.value FROM user_stats INNER JOIN stats ON (user_stats.stat_id = stats.id) WHERE stats.display_name = <foo> AND stats.short_name = <foobar> AND user_stats.user_id = <bar>

Re: Building Browsergames: Implementing a flexible stats system (PHP)

Luke — Thu, 08 Oct 2009 12:38:33 -0000

You need to actually put values into the <foo> and <bar> portions - if you read a little further, the code to do that is later on.

Re: Building Browsergames: Implementing a flexible stats system (PHP)

Luke — Wed, 10 Jun 2009 15:06:16 -0000

You're missing the string formatting that puts arguments into your SQL
statement - add that, and you should be good to go.

Re: Building Browsergames: Implementing a flexible stats system (PHP)

sHyuAn — Wed, 10 Jun 2009 13:26:02 -0000

"SELECT value FROM user_stats WHERE stat_id = (SELECT id FROM stats WHERE display_name = <foo> OR short_name = <foo>) AND user_id = <bar>"

i have inserted this into sql query.. however, the error message came out as below:

"MySQL said:

what should I do now?

Re: Building Browsergames: Implementing a flexible stats system (PHP)

sHyuAn — Wed, 10 Jun 2009 13:13:11 -0000

"SELECT value FROM user_stats WHERE stat_id = (SELECT id FROM stats WHERE display_name = <foo> OR short_name = <foo>) AND user_id = <bar>"

when i put this into sql query, it shows me the error message as below:

"MySQL said:

what should i do?